write an lc 3 assembly language program to read in a two digit decimal number whose 4951758

Write an LC-3 assembly language program to read in a two-digit decimal number whose digits add up to less than 10 and display the sum of those digits in the next line. Sample execution Please enter a two-digit decimal number > 27 The sum of the digits = 9 This is what I have so far. I’m probably approaching thiswrong. .ORIG x3000 LEA R0,PROMPT1 ; Displays first prompt. PUTS ; First number GETC ; Reads char ST R0,CHAR ; Safe keeps char. LD R0,CHAR ; Reload char OUT ; Output a character to the monitor ; Second Number GETC ; Reads char ST R1,CHAR2 ; Safe keeps char. LD R1,CHAR2 ; Reload char OUT ; Output a character to the monitor ; Next Line LD R0,CRLF ; Executes new line. OUT ; Writes char LEA R0,PROMPT2 ; Displays second prompt. PUTS LD R0,CRLF ; Executes new line. OUT ; Writes char LD R0,CHAR ; Reload first char LD R1,CHAR ; Reload second char LD R4,NEG30 ADD R0,R0,R1 ADD R0,R0,R4 OUT ; Displays uppercase. HALT ;************ Data area******************************* PROMPT1 .STRINGZ “Enter a two-digit decimal number> “ PROMPT2 .STRINGZ “The value of the two numbers added togeter>” CHAR .BLKW 2 CHAR2 .BLKW 1 CHAR3 .BLKW 1 NEG30 .FILL #-48 CRLF .FILL #10 .END Attached

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